Create Date Ranges for Consecutive dates in a SQL Server Table

I had recently posted a SQL script to SQL Query to Find out who attended office on Saturday

Shashi commented asking it was possible to create Date Range for all consecutive dates and group them together in such queries. Here is a query to group all the consecutive dates together and create a range out of them.

SAMPLE DATA

DECLARE @TT TABLE (EID int, CheckIn DATETIME)
INSERT INTO @TT VALUES (2, 'April 02, 2010 11:25am')
INSERT INTO @TT VALUES (4, 'April 03, 2010 9:55am')
INSERT INTO @TT VALUES (5, 'April 07, 2010 11:24am')
INSERT INTO @TT VALUES (2, 'April 10, 2010 11:22am')
INSERT INTO @TT VALUES (3, 'April 15, 2010 5:27am')
INSERT INTO @TT VALUES (6, 'April 16, 2010 8:21am')
INSERT INTO @TT VALUES (7, 'April 17, 2010 11:55am')
INSERT INTO @TT VALUES (3, 'April 22, 2010 10:16am')
INSERT INTO @TT VALUES (4, 'April 24, 2010 11:35am')
INSERT INTO @TT VALUES (7, 'April 30, 2010 9:49pm')
INSERT INTO @TT VALUES (2, 'May 01, 2010 9:49am')
INSERT INTO @TT VALUES (5, 'May 02, 2010 10:43am')
INSERT INTO @TT VALUES (3, 'May 03, 2010 11:29am')

QUERY

SELECT MIN(CheckIn) AS BeginRange,
       MAX(CheckIn) AS EndRange
FROM (
SELECT CheckIn,
    DATEDIFF(D, ROW_NUMBER() OVER(ORDER BY CheckIn), CheckIn) AS DtRange
FROM @TT) AS dt
GROUP BY DtRange;

OUTPUT

Date Range SQL Server

at

5 comments:

  1. MartinMay 11, 2010 at 6:17 AM

    What about this?
    This a little bit tricky using NTILE, but split into begin and end range interval.


    select min(checkin) as b,
    max(checkin) as e

    from
    (
    SELECT CheckIn,
    ntile((select (count(*)+1) / 2 from @TT) ) OVER(ORDER BY CheckIn) AS DtRange

    FROM @TT) as dt
    group by dtrange


    Useful?

    ReplyDelete
  2. JibaMay 11, 2010 at 7:30 PM

    Nice work Martin. Did you check the execution plan to see which performs better?

    ReplyDelete
  3. MartinMay 11, 2010 at 11:12 PM

    No,
    my motivation was a non-logic output.
    Why is 2010/04/02 - 03 and 2010/04/07 is alone? And where is 2010/04/16?

    I updated my script due small bug.

    select min(checkin) as b,
    max(checkin) as e
    from
    (
    SELECT CheckIn,
    ntile((select (count(*) / 2)+1 from @TT) ) OVER(ORDER BY CheckIn) AS DtRange

    FROM @TT
    ) as dt
    group by dtrange

    My execution plan costs 12% relative to batch. Original shows 17%.

    Martin

    ReplyDelete
  4. JibaMay 12, 2010 at 12:34 AM

    bug? I think the poster mentions that the query 'groups all the consecutive dates together '

    and where is 2010/04/02 - 03 alone? It is grouped together.
    2010/04/07 and 10 are alone because they do not have any consecutve dates.

    Am I missing your point here? Anyways nice query again.

    ReplyDelete
  5. MartinMay 12, 2010 at 12:45 AM

    Sorry, it was my mistake. Translations "consecutive" into czech has many variants.

    Ok, consecutive means days after day without no day omision.
    From Monday to Wednesday if Tuesday I was also in work.

    I understood consecutive as a
    "first is input", "second one is output".
    (funny how misunderstood can produce brand new approach in querying).

    Keep coding..

    ReplyDelete